Work out? The electric field strength at a point 4cm from source change is #100" N/C"#.what will be the electric field strength at distance of 2cm from the same change? Thanks

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Answer 1 · 2017-12-25T17:24:13

#E_2 = 400" N/C"#

We know that:

#E_1 = kQ/d_1^2#

And:

#E_2=kQ/d_2^2#

We are given that:

#d_2 = 1/2d_1#

Substitute the above into the equation for #E_2#

#E_2= kQ/(d_1/2)^2#

#E_2= kQ/(d_1^2/4)#

#E_2= 4kQ/d_1^2#

Please observe that we may substitute in #E_1#:

#E_2 = 4E_1#

We are given that #E_1 = 100" N/C"#

#E_2 = 4(100" N/C")#

#E_2 = 400" N/C"#