# Write the equation of a circle in standard form whose center is at (3,-2) and has a radius of 11?

Jun 17, 2018

${\left(x - 3\right)}^{2} + {\left(y + 2\right)}^{2} = 121$

#### Explanation:

Formula for a circle:

${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$ where $\left(h , k\right)$ is the center.

${\left(x - 3\right)}^{2} + {\left(y + 2\right)}^{2} = 121$

graph{(x-3)^2+(y+2)^2=121 [-18.16, 21.84, -10.32, 9.68]}