Write the equation of the tangent line of y = 2cosx at x = -pi/2. Help?!
1 Answer
Jul 24, 2017
Explanation:
#•color(white)(x)dy/dx=m_(color(red)"tangent")" at x = a"#
#y=2cosx#
#rArrdy/dx=-2sinx#
#"at "x=-pi/2#
#dy/dx=-2sin(-pi/2)=2#
#"and "y=2cos(-pi/2)=0#
#"equation of tangent using"#
#m=2" and " (x_1,y_1)=(-pi/2,0)#
#y-0=2(x-pi/2)#
#rArry=2x-pi#
