# If x^2+16x+64=0, what is the value of x ?

Apr 22, 2018

$x = - 8$

#### Explanation:

Assuming you're trying to find $x$, you can start by factorizing the equation;

${x}^{2} + 16 x + 64 = 0$

$\left(x + 8\right) \left(x + 8\right) = 0$

From the null factor law, either one of the products would have to equal $0$. In this case, it is $x + 8$.

$x + 8 = 0$

To solve for $x$, move other terms to leave $x$ on its own, which makes

$x = - 8$