#(x-5)^2=8#?

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Answer 1 · 2018-04-03T14:43:52

#x = 5+-2sqrt(2)#

Given:

#(x-5)^2 = 8#

Note that both #2sqrt(2)# and #-2sqrt(2)# are square roots of #8#.

So:

#x-5 = +-2sqrt(2)#

Adding #5# to both sides, we find:

#x = 5+-2sqrt(2)#