Y=2+2x²-5x find vertex of the parabola?

1 Answer
Apr 16, 2018

Vertex is at #(1.25,-1.125)#

Explanation:

# y=2+ 2 x^2 -5 x or y= 2 x^2 -5 x +2# or

# y= 2(x^2 - 2.5 x ) +2# or

# y= 2 {x^2 - 2.5 x + (2.5/2)^2 }- 2(2.5/2)^2 +2# or

# y= 2 {x^2 - 2.5 x + 1.25^2 }- 3.125 +2# or

# y= 2 (x - 1.25)^2 - 1.125 # Comparing with vertex form of

equation #f(x) = a(x-h)^2+k ; (h,k)# being vertex we find

here #h=1.25 , k= -1.125 :.# Vertex is at #(1.25,-1.125)#

graph{2x^2-5x+2 [-10, 10, -5, 5]} [Ans]