Y=e^x.sin^-1.x (diff. With respect to x)?
1 Answer
Apr 18, 2018
Explanation:
#"differentiate using the "color(blue)"product rule"#
#"Given "y=g(x)h(x)" then"#
#dy/dx=g(x)h'(x)+h(x)g'(x)larrcolor(blue)"product rule"#
#g(x)=e^xrArrg'(x)=e^x#
#h(x)=sin^-1xrArrh'(x)=1/(sqrt(1-x^2)#
#rArrdy/dx=e^x/sqrt(1-x^2)+e^xsin^-1x#