# You have 48.3g of solid lithium sulfate. If it has a density of #"2220 g/L"#, what volume will this solid occupy?

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Having trouble with this question

Having trouble with this question

##### 1 Answer

#### Explanation:

The problem tells you that lithium sulfate has a density of **every**

In your case, you know that the mass of an unknown volume of lithium sulfate is equal *conversion factor* to find the volume of the sample.

#48.3 color(red)(cancel(color(black)("g"))) * overbrace(color(purple)("1 L")/(color(blue)(2220)color(red)(cancel(color(blue)("g")))))^("given by the density of lithium sulfate") = color(darkgreen)(ul(color(black)("0.0218 L")))#

The answer is rounded to three **sig figs**, the number of significant figures you have for your values.

If you want, you can convert this to *milliliters* by using the fact that

#"1 L" = 10^3# #"mL"#

You should end up with a volume of