You kick a soccer ball with a speed of 12 m/s at an angle of 21. How long does it take the ball to reach the top of its trajectory?

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Answer 1 · 2018-02-07T16:17:29

The time is #=0.44s#

Resolving in the upwards direction #uarr^+#

Apply the equation of motion

#v=u+at#

The initial velocity is #u=u_0sintheta=12sin21#

The aceleration due to gravity is #g=9.8ms^-2#

At the top of the trajectory #v=0ms^-1#

Therefore,

#0=12sin21-9.8*t#

#t=12(sin21/9.8)#

#=0.44s#