You need to move a 53-kg armoire across the room. You put some cardboard under the feet of the armoire. If you push with a force of 38 N, and the armoire accelerates at 0.20 m/s, what is the coefficient of friction of the cardboard over the carpet?

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Answer 1 · 2018-04-10T12:53:14

#~~ 0,.053#

The net force acting on the armoire is #53" Kg"times 0.2" ms"^-2## = 10.6" N"#.

Thus, the force of friction acting on this is

#38" N"-10.6" N"=27.4" N"#

Now, the normal force acting on the armoire must balance its weight (since there is horizontal acceleration), and thus it is

#53" Kg"times 9.8" ms"^-2= 519.4" N"#.

Thus, the coefficient of kinetic friction is

#(27.4" N")( 519.4" N") ~~ 0.053#