Question

You place a 133 g is placed on a vertical spring. The spring then compresses by 11 cm. What is the stiffness of the spring (in kg/s^2)?

Answer 1

11.85 `"kg/s"^2`

Explanation:

`F = -kx`

Force applied on spring is `"mg"`

`"mg" = -kx`

`k = -"mg"/x = -(133 xx 10^-3 "kg" × "9.8 m/s"^2)/(-11 × 10^-2 "m") = 11.85 "kg/s"^2`