Zinc metal reacts with HCl solution to produce ZnCl2 and H2 gas. What is the volume (in mL) of 0.470 M HCl is required to react with 0.15 g of Zn metal?

1 Answer
Jan 23, 2018

We address the stoichiometric equation.....

Explanation:

#Zn(s) + 2HCl(aq) rarr ZnCl_2(aq) + H_2(g)uarr#

And we work out the molar equivalence of zinc...

#"Moles of zinc"-=(0.0150*g)/(65.4*g*mol^-1)-=2.30xx10^-4*mol.#

And so we want AT LEAST 2 equivs of hydrochloric acid....and we simply take the quotient....

#(4.60xx10^-3*mol)/(0.470*mol*L^-1)xx10^3*mL*L^-1=0.11*mL#...of course we would use a stoichiometric excess...to complete the oxidation reaction....