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Abdur R. has helped students
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Summary of contribution activity by day
On a 22 day streak. Longest streak: 22 days
8 thank you notes
@wricheek-a
Wricheek A.
thank you
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4 weeks ago
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@michael-2
Michael
Like your working.
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4 weeks ago
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Someone from Kolkata, India
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1 month ago
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Abdur R.
I'm an A-level student currently in Yr 13.
17K karma · London
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246 Answers
161 Edits
3 Asked
@abdur-r
Abdur R.
commented
Added a missing "
on
What is the rate law for the following mechanism in terms of the overall rate constant k? Step 1: #A + B leftrightarrow C# (fast) Step 2: # B + C -> D# (slow)
a minute ago
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@abdur-r
Abdur R.
updated
the answer to
What is the rate law for the following mechanism in terms of the overall rate constant k? Step 1: #A + B leftrightarrow C# (fast) Step 2: # B + C -> D# (slow)
.
a minute ago
·
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@abdur-r
Abdur R.
wrote an answer to
How do you evaluate #antiln(-0.7831)#?
.
2 minutes ago
·
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@abdur-r
Abdur R.
updated
the answer to
How do you find the derivative of #(tan^3)(4/x)-(cos^-1)(Lnx)#?
.
4 minutes ago
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@abdur-r
Abdur R.
commented
I think the question may be worded wrong because I can't seem to find 3 consecutive odd integers which add up to 48
on
The sum of three consecutive odd integers is 48, how do you find the largest integer?
2 hours ago
·
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@abdur-r
Abdur R.
commented
This is a perfect square so can be expanded using the identity: #(a+-b)^2-=a^2+-2ab+b^2#.
on
How do you find the product #(8h-4n)^2#?
2 hours ago
·
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@abdur-r
Abdur R.
commented
Answer is correct, just changed some typos which created formatting errors: #lin# to #ln#
on
How do you integrate #4/((x+1)(x-5))# using partial fractions?
yesterday
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@abdur-r
Abdur R.
updated
the answer to
How do you integrate #4/((x+1)(x-5))# using partial fractions?
.
yesterday
·
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@abdur-r
Abdur R.
commented
Your answer can be simplified further: #-clna+clnb=cln(b/a)#
on
How do you integrate #4/((x+1)(x-5))# using partial fractions?
yesterday
·
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@abdur-r
Abdur R.
commented
Changed #1/x-5# to #1/(x-5)#
on
How do you integrate #4/((x+1)(x-5))# using partial fractions?
yesterday
·
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