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Abhishek K. has helped students
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On a 4 day streak. Longest streak: 20 days
13 thank you notes
@just4simple-g
Just4simple G.
thank you!
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22 hours ago
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@aminul-i-2
Aminul I.
Thank you so much for the answer! It's really awesome!
for this
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1 week ago
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Someone from San Francisco, United States
Thank you
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3 weeks ago
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Abhishek K.
Abhishek K. joined Socratic 1 year ago. Abhishek K. hasn't written a biography yet.
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139 Answers
25 Edits
65 Asked
@abhishek-k
Abhishek K.
commented
@Rahul
It cannot be proved because #sin2x+sin4x# is not equal to #tan2x-tan4x#.
on
1)if sin2A+sin4A=1 then proved that, tan2A-tan4A=1 ?
an hour ago
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@abhishek-k
Abhishek K.
wrote an answer to
How to do this question?
.
5 hours ago
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@abhishek-k
Abhishek K.
wrote an answer to
How to verify ((csc^(3)x-cscxcot^(2)x))/(cscx) =1 ?
.
5 hours ago
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@abhishek-k
Abhishek K.
wrote an answer to
How to prove #(1+sinx-cosx)/(1+cosx+sinx)=tan(x/2)#?
.
5 hours ago
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@abhishek-k
Abhishek K.
wrote an answer to
Show that cosÂ²Ï€/10+cosÂ²4Ï€/10+cosÂ² 6Ï€/10+cosÂ²9Ï€/10=2. I am a bit confused if I make CosÂ²4Ï€/10=cosÂ²(Ï€-6Ï€/10) & cosÂ²9Ï€/10=cosÂ²(Ï€-Ï€/10), it will turn negative as cos(180Â°-theta)=-costheta in the second quadrant. How do I go about proving the question?
.
5 hours ago
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@abhishek-k
Abhishek K.
said thanks for an answer to
If # tan (beta/2)=4tan (alpha/2)#,prove that #tan ((beta-alpha)/2)=(3sin alpha)/(5-3cos alpha)#?
.
9 hours ago
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@abhishek-k
Abhishek K.
said thanks for an answer to
Prove that #cot (A/2)- 3cot ((3A)/2) = (4sinA)/(1+2cosA)#?
.
9 hours ago
·
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@abhishek-k
Abhishek K.
said thanks for an answer to
Prove that #cot (A/2)- 3cot ((3A)/2) = (4sinA)/(1+2cosA)#?
.
9 hours ago
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@abhishek-k
Abhishek K.
commented
Thanks and regards
@Ratnaker Mehta
sir for the appreciation.
on
Can anyone prove this please?
yesterday
·
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@abhishek-k
Abhishek K.
commented
@sahil
see
https://socratic.org/questions/if-the-circles-x-2-y-2-2ax-c-2-0-and-x-2-y-2-2by-c-2-0-touch-externally-prove-th
on
If the circles x^2+y^2+2ax+c^2=0 and x^2+y^2+2by+c^2=0 touch each other,prove that 1/a^2+1/b^2=1/c^2?
yesterday
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