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karma
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The question appears to have an unpaired parenthesis that needs to be fixed. Even if we are to assume that the question was intended to say #(3x^2+x+1)-(10(3x^2+x-1))/(3x^2)+x=7# , this solution does not work. In steps 4-5, #10x# was subtracted from the right side but added on the left side, thus making everything after it also incorrect. The more important issue with this solution is that the method used to solve step 10 is incorrect. Currently, you appear to only checking for either #x# or #9x^3+6x^2-48x+10# to be equal to #-10# instead of for all possibilities for which the product is -10. Furthermore, #x=−10# does not work since the left hand side (assuming the red part is correct, which it isn't) equals #79100!=− 10#. (And neither does #x=0#, since the term #(10(3x^2+x-1))/(3x^2)# would be undefined.) In order to solve an equation such as #x(9x^3+6x^2−48x+10)=−10#, one would need to first add #10# to both sides to get #0# on one side of the equation before attempting to solve the polynomial. For reference, here is a desmos graph of the assumed original problem: https://www.desmos.com/calculator/zl9pxhrs6p
on
Solve for x : (3x^2+x+1)-(10(3x^2+x-1)÷ 3x^2+x=7?