Answers edited by Youssuf E.
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If a #1 kg# object moving at #3 m/s# slows down to a halt after moving #8 m#, what is the friction coefficient of the surface that the object was moving over?
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How do you simplify #(24x^3y + 12x^2y^2 - 16xy^3)/(4xy)#?
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If a #2 kg# object moving at #1/2 m/s# slows to a halt after moving #5 m#, what is the coefficient of kinetic friction of the surface that the object was moving over?