Question

Question #a5860

Answer 1

`x = (-pi/4 +k pi) uu (pi/3+kpi)` for `k in ZZ`

Explanation:

Multiplying both sides by `tanx`

`tan^2x+(1-sqrt3)tanx-sqrt3=0` so

`tanx = (-(1-sqrt3)pm sqrt((1-sqrt3)^2-4 sqrt 3))/2={(-1),(sqrt3):}`

or `{(tanx = -1->x=-pi/4 +k pi),(tanx = sqrt3->x=pi/3+kpi):}`

so

`x = (-pi/4 +k pi) uu (pi/3+kpi)` for `k in ZZ`