Question

A sample of dry gas is found to occupy 2.850 L at 22.0°C and .918atm. How many moles of the gas are present?

A sample of dry gas is found to occupy 2.850 L at 22.0°C and .918atm. How many moles of the gas are present?

Answer 1

0.108 moles of the gas are present.

Explanation:

To solve this problem, we need to use the ideal gas law:

`PV=nRT`

`P` is pressure in atmospheres, `V` is volume in liters, `n` is moles, `R` is the universal gas constant, and `T` is the temperature in Kelvins.

First, convert `2.0^oC` to Kelvins by adding 273:

`22.0^oC + 273 = 295K`

Plug the known values into the equation and solve for `n` (moles).

`(0.918)(2.850)=(n)(0.08206)(295)`

`n=((0.918)(2.850))/((0.08206)(295))=0.108` moles