A sample of dry gas is found to occupy 2.850 L at 22.0°C and .918atm. How many moles of the gas are present?

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A sample of dry gas is found to occupy 2.850 L at 22.0°C and .918atm. How many moles of the gas are present?

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Answer 1 · 2018-02-28T21:14:27

0.108 moles of the gas are present.

Explanation:

To solve this problem, we need to use the ideal gas law:

$P V = n R T$ $PV=nRT$

$P$ $P$ is pressure in atmospheres, $V$ $V$ is volume in liters, $n$ $n$ is moles, $R$ $R$ is the universal gas constant, and $T$ $T$ is the temperature in Kelvins.

First, convert ${2.0}^{o} C$ $2.0^oC$ to Kelvins by adding 273:

${22.0}^{o} C + 273 = 295 K$ $22.0^oC + 273 = 295K$

Plug the known values into the equation and solve for $n$ $n$ (moles).

$(0.918) (2.850) = (n) (0.08206) (295)$ $(0.918)(2.850)=(n)(0.08206)(295)$

$n = \frac{(0.918) (2.850)}{(0.08206) (295)} = 0.108$ $n=((0.918)(2.850))/((0.08206)(295))=0.108$ moles

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A sample of dry gas is found to occupy 2.850 L at 22.0°C and .918atm. How many moles of the gas are present?