Question

Question #4badc

Answer 1

0.8 mol

Explanation:

As per the equation

`H_2` (g) + `O_2` (g) -----> 2`H_2`O (l)

1 mol of `O_2` is required to produce 2 moles of `H_2`O

x mol of `O_2` is required to produce 1.60 moles of `H_2`O

setting up the ratio , we get

(1 mol of `O_2` / X mol of `O_2`) = (2 mol of `H_2`O / 1.6 mol of `H_2`O)

1 / x = 2 /1.6

1 x 1.6 = 2.x

1.6 = 2x

x= 0.8 mol