What is the concentration with respect to #gL^-1# of a solution prepared by dissolving #1.72g# of #"potassium permanganate"# in #60.0*mL# of water?

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Answer 1 · 2017-04-22T08:59:18

Well, is this not the quotient...........

...........??

#("Mass of potassium permanganate")/("Volume of solution")#

#=(1.72*g)/(60*mL)=0.0287*g*mL^-1#.

#=(1.72*g)/(0.060*L)=28.7*g*L^-1.#

Agree?

What is the concentration with respect to #g*L^-1# of a solution prepared by dissolving #1.72*g# of #"potassium permanganate"# in #60.0*mL# of water?