What is the concentration with respect to $gL^-1$ of a solution prepared by dissolving $1.72g$ of $"potassium permanganate"$ in $60.0*mL$ of water?

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Answer 1 · 2017-04-22T08:59:18

Well, is this not the quotient...........

...........??

$("Mass of potassium permanganate")/("Volume of solution")$

$=(1.72*g)/(60*mL)=0.0287*g*mL^-1$ .

$=(1.72*g)/(0.060*L)=28.7*g*L^-1.$

Agree?

What is the concentration with respect to g*L^-1g*L^-1 of a solution prepared by dissolving 1.72*g1.72*g of "potassium permanganate""potassium permanganate" in 60.0*mL60.0*mL of water?