How do you find the equation of the circle with center at (1, 3) and tangent to the line whose equation is x – y + 2 =0?

1 Answer
Jim H
Sep 16, 2016

There is no such circle.

Explanation:

The line #x-y+2=0# contains the point #(1,3)#.

A line through the center of a circle is not tangent to the circle.

Therefore, there is no circle matching the description.

Suggestion

I saw the answer when I tried to draw a sketch of the situation. The line has slope-intercept equation #y=x+2#. Whe I tried to graph the line starting ay the #y# intercept and using the slope, it ran through the point #(1,3)#.

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