How do you graph using slope and intercept of #2x-3y=7#?

1 Answer
Apr 2, 2018

See below

Explanation:

Remember that slope intercept form is #y = mx + b# where m is slope and b is the y intercept

So we must put the function in slope intercept form as such:

#2x-3y=7#

#-3y = -2x + 7#

#y = 2/3x - 7/3#

To graph the equation, we place a point on the graph where x = 0 (y intercept) at the value #y =-7/3#, then we draw a line with a slope of #2/3# that runs through that line.
graph{y = (2/3x) - (7/3) [-3.85, 6.15, -3.68, 1.32]}