How do you write #9^(3/2) = 27# in log form?

1 Answer
Bill K.
Jun 16, 2015

#log_{9}(27)=3/2#

Explanation:

For #b>0#, #b!=1# and #y>0#, the symbol #x=log_{b}(y)# represents the unique real number such that #b^{x}=y# (it's the unique solution of that equation).

Since #x=3/2# is the unique solution of the equation #9^{x}=27#, it follows that #log_{9}(27)=3/2#.

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