Question

0.314 mol of a diatomic molecule has a mass of 22.26g. How would you identify the molecule?

Answer 1

We take the quotient `"mass"/"molar quantity"`............, and we indentify the molecule as `Cl_2`........

Explanation:

And thus `"mass"/"molar quantity"=(22.26*g)/(0.314*mol^-1)`

`-=70.9*g*mol^-1` WITH RESPECT TO `X_2`, and thus the molar mass, with respect to `X` was `35.45*g*mol^-1`, and clearly `X=Cl`, i.e. `X_2-=Cl_2`.

As a tip, which I would expect A2 students, and certainly 1st year undergraduates, to know, `"ALL of the elemental gases"` (save the Noble Gases), `"dihydrogen, dinitrogen, dioxygen, dihalogen,"` are BINUCLEAR, i.e. `H_2`, `N_2`, `X_2` etc.

And of course `Br_2` is a room temperature liquid, and `I_2` is a room temperature solid.