0.550 moles of NaCl are dissolved in 1.95 L of water. Calculate the molarity of the NaCl solution. ?

1 Answer
May 23, 2018

[NaCl(aq)]=0.282*mol*L^-1

Explanation:

We assume reasonably that the volume of the solvent remains constant during dissolution....and so we simply take the quotient...

"[NaCl]"="moles of salt (mol)"/"volume of solution (L)"=(0.550*mol)/(1.95*L)

-=??*mol*L^-1...what are the concentrations with respect to Na^+ and Cl^-?