0.550 moles of NaCl are dissolved in 1.95 L of water. Calculate the molarity of the NaCl solution. ?

1 Answer
anor277
May 23, 2018

#[NaCl(aq)]=0.282*mol*L^-1#

Explanation:

We assume reasonably that the volume of the solvent remains constant during dissolution....and so we simply take the quotient...

#"[NaCl]"="moles of salt (mol)"/"volume of solution (L)"=(0.550*mol)/(1.95*L)#

#-=??*mol*L^-1#...what are the concentrations with respect to #Na^+# and #Cl^-#?

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