Question

1\16=64^4x-3. ? Solve the exponential equation please

Answer 1

`x=7/12`

Explanation:

`1/16=64^(4x-3)`
`1=16xx64^(4x-3)`
`16=4^2`
`64=4^3`
`16xx64=4^2xx4^3`

`1=4^2xx(4^3)^(4x-3)`
`(4^3)^(4x-3)=4^(3(4x-3))`
`1=4^2xx4^(3(4x-3))`
`1=4^0`
`4^2xx4^(3(4x-3))=4^(2+3(4x-3))`
`4^0=4^(2+3(4x-3))`

Equating the indices
`0=2+3(4x-3)`
`-2=3(4x-3)`
`-2=12x-9`
`-2+9=12x`
`7=12x`

`x=7/12`