Calculate the molar concentration of the solution in 2 liters of which contained 58 g of lead(II) nitrate?

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Answer 1 · 2018-04-12T16:39:07

The concentration of the solution will be #"0.09 M"#.

The molar mass of #"Pb"("NO"_3)_2: " 332.2 g/mol"#

So

#"58 g Pb"("NO"_3)_2 * "1 mol"/("331.2 g Pb"("NO"_3)_2) = "0.0175 mol of Pb"("NO"_3)_2#

The formula for the molar concentration is

#"M"="mol"/"L"#

Since #"L"# is given and the mol is calculated,

#"M" = "0.0175 mol"/"2 L"#

The answer will be around #"0.0875 M"#. However, you need only one sigfig, so you round it, which gives you #"0.09 M"#.