100ml of 0.5N NaOH solution is added to 10ml of 3N H2SO4 solution and 20ml of 1N HCl solution.The nature of the mixture is ?

1 Answer
anor277
Oct 15, 2017

Should not you tell us this?

Explanation:

The basic equation is.....

#"Molarity"="Moles of solute"/"Volume of solution"#

And thus #"moles of solute"="volume"xx"molarity"#.

And so we got.....

#n_(NaOH)=100*mLxx10^-3*L*mL^-1xx0.5*mol*L^-1=0.05*mol#

And you do the same thing with the other concentrations.....and sum the concentrations of hydroxide ions, and protium ions....you treat sulfuric acid as a diacid....

Related questions
Impact of this question
3969 views around the world
You can reuse this answer
Creative Commons License