Question

2× 3√4+7× 3√32- 3√50?

Answer 1

`12+69sqrt(2)`

Explanation:

Since
`sqrt(4)=2`
`sqrt(32)=4*sqrt(2)`
`sqrt(50)=5*sqrt(2)`
we get
`12+84sqrt(2)-15*sqrt(2)`
This is
`12+69sqrt(2)`

Answer 2

`12+69sqrt2`

Explanation:

`6sqrt4+21sqrt32-3sqrt50`

`sqrt4=2`

`sqrt32=4sqrt2`

`sqrt50=5sqrt2`

`12+84sqrt2-15sqrt2`

`12+69sqrt2`

Answer 3

`12+69sqrt2`

Explanation:

`"using the "color(blue)"law of radicals"`

`•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)`

`"simplifying the radicals gives"`

`sqrt4=2`

`sqrt32=sqrt(16xx2)=sqrt16xxsqrt2=4sqrt2`

`sqrt50=sqrt(25xx2)=sqrt25xxsqrt2=5sqrt2`

`"substituting values into the expression"`

`2xx(3xx2)+7xx(3xx4sqrt2)-(3xx5sqrt2)`

`=2xx6+(7xx12sqrt2)-15sqrt2`

`=12+84sqrt2-15sqrt2=12+69sqrt2`