Question

2-a coin is tossed three times, then what is the probability of tossing three heads in succession?

Answer 1

one in eight = `1/8`

Explanation:

When we are looking at events that are independent (where the outcome of one event does not affect the outcome of any later events), the probability of a sequence of events happening in a certain manner is calculated by multiplying the probability of each individual together:

P(event1 and event2 and event 3 etc.) = P(event1) x P(event2) x P(event3) x etc.

So, since the probability of each toss coming up heads is `1/2`, the probability of this happening three times in succession is:

`P(HHH) = P(H) xx P(H) xx P(H) = 1/2xx1/2xx1/2 = 1/8`