27x^3-64y^3?

factoring

1 Answer
Nov 2, 2017

(3x-4y)(9x^2+12xy+16y^2)

Explanation:

27x^3-64y^3
=(3x)^3-(4y)^3
=(3x-4y)[(3x)^2+(3x)(4y)+(4y)^2]
=(3x-4y)(9x^2+12xy+16y^2)

Noted that:

a^3-b^3=(a-b)(a^2+ab+b^2)
a^3+b^3=(a+b)(a^2-ab+b^2)