295 mL of a 1.00 M ammonium chloride (#NH_4Cl#) solution is diluted with 2.25 L of water. What is the new concentration in molarity?

1 Answer
anor277
May 24, 2016

Approx. #0.13*mol*L^-1#

Explanation:

#"Concentration"# #=# #"Number of moles"/"Volume of solution"#.

Initially, we have #0.295*Lxx1.00*mol*L^-1# #NH_4Cl# #=# #??*mol#

Finally this molar quantity is dissolved in a #2.25*L# volume.

#"Concentration"# #=# #(0.295*Lxx1.00*mol*L^-1)/(2.25*L)# #=# #??mol*L^-1#

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