Question

2Cu2S + 3O2 = 2Cu2O + 2SO2 If the mass of Cu2S in the mixture is 14.0 g calculate the number of mole oxygen gas reacted? 5marks

Answer 1

Approx.

Explanation:

We gots…

`underbrace(2Cu_2S(s)+ 3O_2(g))_"414.3 g" rarr underbrace(2Cu_2O+2SO_2(g))_"414.3 g"`

Chemical change CONSERVES MASS and CHARGE absolutely, and in the given reaction we have indicated mass equivalence of products and reactants....

We start with a `14*g` mass of cuprous sulfide, a molar quantity of `(14*g)/(159.16*g*mol^-1)=0.0880*mol`

...and given the stoichiometric reaction, which you have provided

....a mass of `3/2xx0.0880*molxx32.00*g*mol^-1=4.22*g` with respect to dioxygen gas...

Using the same principle, you should be able to determine the masses of `"cuprous oxide"`, and `"sulfur dioxide"`...