#2H_2S + SO_2 -> 2H_2O +3S# what is the oxidizing agent? What is the reducing agent?

1 Answer
P dilip_k
Apr 6, 2018

Given equation

#2H_2S + SO_2 -> 2H_2O +3S#

Changes in Oxidation Numbers

#2stackrelcolor(red)(+1)H_2stackrelcolor(red)(-2)S + stackrelcolor(red)(+4)Sstackrelcolor(red)(-2)O_2 -> 2stackrelcolor(red)(+1)H_2stackrelcolor(red)(-2)O +3stackrelcolor(red)(0)S#

Here ON of #S# atom in #stackrelcolor(red)(+1)H_2stackrelcolor(red)(-2)S# increases from #-2to0# and the ON of #S# atom in #stackrelcolor(red)(+4)Sstackrelcolor(red)(-2)O_2# decreases from #+4to 0#.

So oxidation of #S# in #H_2S# and reduction of #S# in #SO_2# occur here.

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