2NO(g) + O2 (g) --> 2NO2 How many moles of O2 are required to produce 92.0 g NO2?

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#2NO(g) + O_2 (g) -> 2NO_2#

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Answer 1 · 2018-04-28T16:16:19

#2NO(g) + O_2 (g) -> 2NO_2(g)#

This equation tells us that for every #2# moles of #NO_2# formed ; we require #1# mole of #O_2#.

So given amount of #NO_2 # formed #= 92g#

Molar mass of #NO_2 = (14+16xx2)g=46g#

So number of moles of #NO_2# formed #=92/46=2#moles

#:.# The mole of #O_2# required here #=1# mole