# 2NO(g) + O2 (g) --> 2NO2 How many moles of O2 are required to produce 92.0 g NO2?

## $2 N O \left(g\right) + {O}_{2} \left(g\right) \to 2 N {O}_{2}$

Apr 28, 2018

$2 N O \left(g\right) + {O}_{2} \left(g\right) \to 2 N {O}_{2} \left(g\right)$

This equation tells us that for every $2$ moles of $N {O}_{2}$ formed ; we require $1$ mole of ${O}_{2}$.

#### Explanation:

So given amount of $N {O}_{2}$ formed $= 92 g$

Molar mass of $N {O}_{2} = \left(14 + 16 \times 2\right) g = 46 g$

So number of moles of $N {O}_{2}$ formed $= \frac{92}{46} = 2$moles

$\therefore$ The mole of ${O}_{2}$ required here $= 1$ mole