Question

How do you solve `(2x-3)(3x+7)=0` using the factoring method?

Answer 1

`x=-7/3" or "x=3/2`

Explanation:

`"the factors are in factored form and the product is"`
`"equal to zero"`

`"in this case equate each factor to zero and solve for x"`

`3x+7=0rArrx=-7/3`

`2x-3=0rArrx=3/2`

Answer 2

`x = 3/2 or x= -7/3`

Explanation:

`(2x-3)(3x+7) = 0`

Since there are two factors multiplied to equal to zero, that means we can find `x` by setting each factor to zero:

`2x - 3 = 0` and `3x + 7 = 0`

`2x = 3` `quadquadquad` and `quadquadquadquad3x = -7`

`x = 3/2` `quadquadquad` and `quadquadquadquadquadx = -7/3`

Hope this helps!