2x + 7 < 1 How can I solve x in this inequality?

1 Answer
Apr 30, 2018

#x=ZZ^-# which is less than #-4#

Explanation:

For any non-negative integer, only 0 is less than 1. But it is impossible to make #2x+7# less than 1 without making #x# a negative number.
(it is going to be too complex with all possible number values of x so we will assume that #x# is an integer, which means that it is a number like 1,2,3,4, or 0,-1,-2,-3,-4 and so on)
the biggest integer value of #x# which can make #2x+7 # less than 1 is #-4#
#x# thus is a negative integer which is equal to or less than #-4#