#3.534 x 10^3# milligrams of #H_2# is equal to how many liters of #H_2#?

1 Answer
May 7, 2018

Answer:

Dihydrogen gas occupies a volume that is a function of TEMPERATURE and PRESSURE....

Explanation:

...we could specify standard conditions of temperature and pressure, #1*atm;298 *K#, and work from there....which equation do I use here?

#V=(nRT)/P=((3.354*g)/(2.019*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx298*K)/(1*atm)#

...I make this about #41*L#...but you will have to specify your terms.