Question

`3.534 x 10^3` milligrams of `H_2` is equal to how many liters of `H_2`?

Answer 1

Dihydrogen gas occupies a volume that is a function of TEMPERATURE and PRESSURE....

Explanation:

...we could specify standard conditions of temperature and pressure, `1*atm;298 *K`, and work from there....which equation do I use here?

`V=(nRT)/P=((3.354*g)/(2.019*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx298*K)/(1*atm)`

...I make this about `41*L`...but you will have to specify your terms.