3 cm high object is placed 25 cm in front of a convex lens of focal length 15 cm. What is the position, nature and size of the image? Physics 1 Answer ali ergin Aug 9, 2016 #"image distance:"37.5 " cm"# #"image height: :"4.5" cm"# #"please look at animation"# Explanation: #c:"height of object"# #g:"image's height"# #u:"object's distance from lens"# #f:"focal length of object"# #u^':"image's distance from lens" # #"you can use the formula "1/f=1/u+1/u^'# #"plug the given values into formula"# #f=15" cm"# #u=25 cm"# #u^'=?# #1/15=1/25+1/u^'# #1/u^'=1/15-1/25# #1/u^'=(5-3)/75# #1/u^'=2/75# #u^'=75/2# #u^'=37.5" cm"# #g/c=u^'/u# #g/3=(37.5)/25# #g=(3*37.5)/25# #g=4.5" cm"# Answer link Related questions How do I determine the molecular shape of a molecule? What is the lewis structure for co2? What is the lewis structure for hcn? How is vsepr used to classify molecules? What are the units used for the ideal gas law? How does Charle's law relate to breathing? What is the ideal gas law constant? How do you calculate the ideal gas law constant? How do you find density in the ideal gas law? Does ideal gas law apply to liquids? Impact of this question 3380 views around the world You can reuse this answer Creative Commons License