3 cm high object is placed 25 cm in front of a convex lens of focal length 15 cm. What is the position, nature and size of the image?

1 Answer
Aug 9, 2016

#"image distance:"37.5 " cm"#
#"image height: :"4.5" cm"#
#"please look at animation"#

Explanation:

enter image source here

#c:"height of object"#
#g:"image's height"#
#u:"object's distance from lens"#
#f:"focal length of object"#
#u^':"image's distance from lens" #

#"you can use the formula "1/f=1/u+1/u^'#

#"plug the given values into formula"#

#f=15" cm"#
#u=25 cm"#
#u^'=?#

#1/15=1/25+1/u^'#

#1/u^'=1/15-1/25#

#1/u^'=(5-3)/75#

#1/u^'=2/75#

#u^'=75/2#

#u^'=37.5" cm"#

#g/c=u^'/u#

#g/3=(37.5)/25#

#g=(3*37.5)/25#

#g=4.5" cm"#