3NO₂(g) + H₂O(l) → 2HNO₃(l) + NO(g). If 3.9 mol NO₂ and 0.50 mol H₂O combine and react completely, how many moles of the excess reactant are present after the reaction is complete?
2.4 mol of
This is similar to an earlier question on Socratic, so I will simply go through the steps.
The balanced equation is
Step 1. Identify the limiting reactant.
Step 2. Calculate the moles of excess reactant used up.
Step 3. Calculate the moles of excess reactant left over.