# Question #b2eb4

Feb 1, 2014

Lead would have a standard electron configuration of

$1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10} 4 {p}^{6} 5 {s}^{2} 4 {d}^{10} 5 {p}^{6} 6 {s}^{2} 4 {f}^{14} 5 {d}^{10} 6 {p}^{2}$

The noble gas in the row above lead is xenon.

We can replace $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10} 4 {p}^{6} 5 {s}^{2} 4 {d}^{10} 5 {p}^{6}$ with the symbol [Xe] and rewrite the noble gas configuration of lead as

$\left[X e\right] 6 {s}^{2} 4 {f}^{14} 5 {d}^{10} 6 {p}^{2}$