# Question #14194

##### 1 Answer

let us write this as equation;

1 volume of Nitrogen / 3 volume of Hydrogen (a)

if we start with 5 L of Nitrogen , X volumes of Hydrogen will be needed.

let us write this as equation;

5 L of Nitrogen / X L of Hydrogen (b)

equate (a) and (b)

1/3 = 5/X

cross multiply 1.X = 3.5 , X=15 L

2CO +

as per this equation, 2 volumes of Carbon Monoxide , needs 1 volume of Oxygen . The reaction produces two volumes of Carbon dioxide.

let us write this as equation;

2 volume of Carbon Monoxide / 2 volumes of carbon dioxide (a)

if we start with 75 L of Carbon monoxide , X volumes of carbon dioxide will be produced.

let us write this as equation;

75 L of CO / X L of C

equate (a) and (b)

2/2 = 75/X

cross multiply 2.X = 2 . (75) , X= 75 L

2 volume of Carbon Monoxide / 1 volumes of oxygen (a)

if we start with 75 L of Carbon monoxide , X volumes of oxygen will be needed.

75 L of CO / X L of

equate (a) and (b)

2/1= 75 /X , 2.X = 75 x 1 , 2X =75 , X= 37.5 L