Question

Question #3f1d9

Answer 1

For this solution, since the reaction is not at Standard Temperature and Pressure (STP), you will need to use the Ideal Gas Law to solve for moles of `CO_2` and then Stoichiometry to solve for the grams of `CaCO_3`.

To begin with we find the knowns and unknowns for the Ideal Gas Law, PV = nRT.

P = 1.00 atm
V = 3.45 L
n = ??
R = 0.0821 `(atm L)/(mol K)`
T = 298 K

PV = nRT can be rearranged `n = (PV)/(RT)`

`n = ((1.00 atm)(3.45 L))/((.0821 (atmL)/(molK))(298K))`

n = 0.14 moles `CO_2`

Now you can use the balanced chemical equation and stoichiometry to solve for the grams of `CaCO_3`

moles `->` moles `->` grams

`0.14 mol CO_2 x (1 mol CaCO_3)/(1 mol CO_2) x (100.0869 g CaCO_3)/(1 mol CaCO_3) = 14.01 g CaCO_3`

I hope this was helpful.
SMARTERTEACHER