Question

You have 75.0 grams of C2H2Cl4, how many L of Cl2 do you have?

Answer 1

So, you're given 75.0 grams of `C_2H_2Cl_4` and you want to find how many L of `Cl_2`.

Reaction: `2Cl_2` + `C_2H_2` --> `C_2H_2Cl_4`

Understand the information you need to fill in your conversion factors.
You'll want to know:

1. How many grams are in 1 mol C2H2Cl4 (167.84 g) [added atomic weight from periodic table]
2. Mol to mol ratio of Cl2 and C2H2Cl4 (2:1) [given in reaction]
3. How many liters are in a mole (22.4 L/mol) [universal]

Then, you want to set up your conversion factor.
`75.0g C_2H_2Cl_4` x `("1 mol "C_2H_2Cl_4)/("167.84g "C_2H_2Cl_4)` x `("2 mol "Cl_2)/("1 mol "C_2H_2Cl_4)` x `(22.4 L)/( 1 mol)`= ?