Question

Question #f076a

Answer 1

You always start with the balanced chemical equation, an ICE table, and the `K_(sp)` expression.

The balanced chemical equation is

BaSO₄(s) ⇌ Ba²⁺(aq) + SO₄²⁻(aq)
I/mol·L⁻¹: -; 0; 0
C/mol·L⁻¹: -; +`x`; +`x`
E/mol·L⁻¹: -; `x`; `x`

`K_(sp)` = [Ba²⁺][ SO₄²⁻] = `x × x = x^2` = 1.07 ×10⁻¹⁰

`x = √(1.07 ×10⁻¹⁰)` = 1.03 × 10⁻⁵

Solubility = `x` mol/L = 1.03 × 10⁻⁵ mol/L

Hope this helps.