# Question ccd7d

Apr 23, 2014

The equation to solve this problem is as follows:

$N a$ ($\text{number of atoms"/"particles}$) =

$n$ ("no." "of moles")# $\cdot$ $\text{N(Avogadro's number)}$

In your example, you would sub in 1 mole into n, then sub in Avogadro's number as such:

$N a$ = $\left(1 \text{ mol}\right) \cdot \left(6.02 x {10}^{23}\right)$
$N a$ = $6.02 \cdot {10}^{23}$

Now, because you know that there is 3 times as many chlorine atoms "Cl3”, you multiply this number by 3:

$\left(6.02 x {10}^{23}\right) \cdot \left(3\right)$ = $1.81 x {10}^{24} \text{ atoms}$

Hope this helps! :)