Question

Question #ccd7d

Answer 1

The equation to solve this problem is as follows:

`Na` (`"number of atoms"/"particles"`) =

`n` (`"no." "of moles")` `*` `"N(Avogadro's number)"`

In your example, you would sub in 1 mole into n, then sub in Avogadro's number as such:

`Na` = `(1" mol")*(6.02x10^23)`
`Na` = `6.02 * 10^23`

Now, because you know that there is 3 times as many chlorine atoms "Cl3”, you multiply this number by 3:

`(6.02 x 10^23)*(3)` = `1.81 x 10^24 " atoms"`

Hope this helps! :)