Question #a19e0

1 Answer
Ernest Z.
Jul 25, 2014

The concentration of the NaOH is 0.158 mol/L.

The steps involved are:

  1. Write the balanced chemical equation.
  2. Calculate the moles of NaOH.
  3. Calculate the molarity of the NaOH.

Step 1

The balanced chemical equation is

HCl + NaOH → H₂O + NaCl

Step 2

Moles of NaOH = 0.025 00 L HCl × #(0.273"mol HCl")/(1"L HCl") × (1"mol NaOH")/(1"mol HCl")# =

0.006 825 mol NaOH (3 significant figures + 1 guard digit)

Step 3

Molarity of NaOH = #"moles"/"litres" = (0.006 825"mol")/(0.04321"L")# = 0.158 mol/L

Note: The answer can have only 3 significant figures, because that is all you gave for the molarity of the HCl. If you need more precision, you will have to recalculate.

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