Question

Question #1e06a

Answer 1

Let's assume the `O_2` is at STP conditions. The mass of oxygen would be 2.86g.

Assuming STP conditions allows us to use the molar volume of a gas which says that 1mol = 22.4L.

First let's calculate how many moles of oxygen are present, then convert moles to grams.

2L x `(1mol)/22.4L` x `(32.00g)/(1mol)` = 2.86g Oxygen